prove ODC=OBC

CMI 2019 B4: In a parallelogram ABCD, O is interior point AOB+DOC=180, prove ODC=OBC

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In figure, ΔODC ~ ΔOBA, ∠BOC = 125 and ∠CDO = 70 Find ∠DOC, ∠DCO and ∠OAB | Q2 EX 6.3 class 10

O\' is an interior point of a parallelogram ABCD. Prove that : area of `Delta AOB + \' area of \' De

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In Fig 6.35 Triangle ODC Similar Triangle OBA Angle BOC Is Equal To 125° And Angle CDO Is Equal To

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